0=-16x^2+92x-76

Solution for 0=-16x^2+92x-76 equation:

0=-16x^2+92x-76

We move all terms to the left:

0-(-16x^2+92x-76)=0

We add all the numbers together, and all the variables

-(-16x^2+92x-76)=0

We get rid of parentheses

16x^2-92x+76=0

a = 16; b = -92; c = +76;
Δ = b2-4ac
Δ = -922-4·16·76
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-60}{2*16}=\frac{32}{32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+60}{2*16}=\frac{152}{32}
=4+3/4
$